Question

5. Srikanth's age is three times the age of Rahul. Rahul is half of Arun's age.
If their average age is 16, what is Srikanth's age? please write in linear equation way

Answer 1

 Units are ignored in calculation.

Answer:

24 year

Step-by-step explanation:

  Let the age of Arun be 2a.

So, age of Rahul = half of Arun's age

                   = 1 / 2  of 2a

                   = a

So,

    age of Srikanth = 3 times of Rahul's age

                = 3 * a

                = 3a

Here,

 ⇒ Average of ages = 16

⇒ ( sum of ages / 3 ) = 16

⇒ ( 2a + a + 3a ) / 3 = 16

⇒ 6a / 3 = 16

⇒ 2a = 16

⇒ a = 16/2 = 8

     Hence,

Age of Srikanth = 3a = 3( 8 ) = 24 year

Answer 2

Answer:

$\star\:\textsf{Let the Age of Arun's be n years.}\\\\\star\:\textsf{Rahul = Half of Arun's = }\sf\dfrac{n}{2}\\\\ \star\:\textsf{Srikanth = 3 times of Rahul = }\sf\dfrac{3n}{2}$

$\rule{130}{1}$

$\underline{\bigstar\:\boldsymbol{According\:to\:the\:Question :}}$

$\dashrightarrow\sf\:\: Average=\dfrac{Arun+Rahul+Srikanth}{3}\\\\\\\dashrightarrow\sf\:\:16=\dfrac{n+\frac{n}{2}+\frac{3n}{2}}{3}\\\\\\\dashrightarrow\sf\:\:16 \times 3 = \frac{2n + n + 3n}{2}\\\\\\\dashrightarrow\sf\:\:16 \times 3 \times 2 = 2n + n + 3n\\\\\\\dashrightarrow\sf\:\:16 \times 6 = 6n\\\\\\\dashrightarrow\sf\:\: \dfrac{16 \times 6}{6} = n\\\\\\\dashrightarrow\sf\:\:n = 16$

$\rule{180}{2}$

$\underline{\bigstar\:\boldsymbol{Age\:of\: Srikanth :}}$

$:\implies\sf Srikanth=\dfrac{3n}{2}\\\\\\:\implies\sf Srikanth=\dfrac{3 \times 16}{2}\\\\\\:\implies\sf Srikanth=3 \times 8\\\\\\:\implies\underline{\boxed{\sf Srikanth=24\:years}}$

⠀

$\therefore\:\underline{\textsf{Hence, the age of Srikanth is \textbf{24 years}}}.$