Question

5. State the no of solutions.
3x + 2y-5=0
2x-Y=3y​

Answer 1

Answer:

there can be infinitely many number of solutions to the given equation as a line can be extended to both of its sides.

for instance,

3 X + 2 y - 5 = 0

3 X + 2y = 5

let X = 0

then, 3(0) + 2y = 5

2y = 5

y = 5/2

let X = 1

then, 3(1) + 2y = 5

2y = 5-3

y = 2/2 = 1

like this only you can find infinitely many solutions to any given equation