Question

5 students appear in an examination .in how many ways can the result be announce​

Answer 1

Answer:

120

Step-by-step explanation:

There are 5 students who can come 1st .

As one student will be 1st , 4 students can come 2nd .

three students can come 3rd , 2 students can come 4th and 1 student will be 5th .

No. of ways = 5×4×3×2×1 = 120

Answer 2

In 32 ways the result can be announced

Solution:

Given that,

5 students appear in an examination

To find: Number of ways the result can be announced

We know that,

There are two possibility for each student either fail or pass

Number of students = 5

Then, number of ways for the result is given as:

$Number\ of\ ways = 2^n$

Where, n is the number of students

$Number\ of\ ways = 2^5\\\\Number\ of\ ways = 32$

Thus, in 32 ways the result can be announced

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