(5) Subbu starts from a point O at 10.00 am , overtakes Ajay, who is moving in the same direction, at 11.00 a.m. and Bhuvan moving in the opposite direction at 12.00 (noon). If the speed of Bhuvan is one fourth the speed of Subbu, at what time will Ajay and Bhuvan cross each other.?
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dko alam guys
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dko alam guys
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(if Ajay is taken at rest)
at 4 PM
as let speed of sabbu be x km/h
speed of bhuvan x/4
distance b/w bhuvan and Ajay = x = x/4 * required time
required time=4 hr later
i.e 4 pm
*otherwise if Ajay is moving constantly
then it can not be determined as speed of Ajay is not given.
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