5 sweets are remain left due to giving 3 sweet per one child from total sweet for some children.if it would be given 5 sweet per one children,then the extra 13 sweet would require for total children.then how many children and how many sweet in first ?(please give proper answer with proper explanation if you know)
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1
Answer:
no of children=9 and no of sweets=32
Step-by-step explanation:
let y be the no of children and x be the no of sweets.
A/Q
x=3y+5 -(1)
and in another situation
x=5y-13 -(2)
from (1) and (2)
x=32 and y=9
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Answer:
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