Question

5. Take a = -6, b = 9, c = 5 and verify that
(1) a+b=b+ a
(ii) a-bis not equal to b-a
(iii) a + (b + c) = (a + b) + c
(iv) a - (b-c)+(a - b) - c
(v) b +0=b​

Answer 1

Step-by-step explanation:

I) -6+9=9+(-6)

3=9-6

3=3

since LHS =RHS

II) a-b=b-a

-6-9=9-(-6)

-15=15

hence LHS is not equal to RHS

III) a+(b+c)=(a+b)+c

-6+(9+5)=(-6+9)+5

-6+14=3+5

8=8

hence LHS =RHS

iv)-6-(9-5)+(-6-9)-5

-6-4+(-15)-5

-10-15-5

-25-5

-30

v) 9+0=9

hence LHS = RHS

Hence verified

Answer 2

Step-by-step explanation:

a+b = b+a

-6+9 = 9+-6

=3. =3 ( proved)

a-b not equal to b-a

-6-9=-15

9-6=3 (proved)