Math, asked by geethasrinivasini, 2 months ago

5. Takesh solued some problems of exponents in the following way. Do you agree with the solutions? If not why? Justify your argument. 1. x‐³ × x‐² = x‐⁶ 2. x³ / x² = x⁴ ​

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Answers

Answered by tennetiraj86
3

Step-by-step explanation:

Given Questions-Solutions:-

i)x-³×x-²=x-⁶

I do not agree with Rakesh.

He did wrong .

Justification:-

x-³×x-²

It is in the form of a^m×a^n

a^m×a^n=a^(m+n)

=>x^(-3-2)

=>x-⁵

x-³×x-²=x-⁵

_______________________________

ii)x³/x²=x⁴

I do not agree with Rakesh.

He did wrong.

Justification:-

x³/x²

It is in the form of a^m/a^n

a^m/a^n=a^(m-n)

=>x³-²

=>x¹

=>x

x³/x²=x

_______________________________

iii)(x²)³=x^2³=x⁸

I do not agree with Rakesh

He did wrong

Justification:-

(x²)³

It is in the form of (a^m)^n

(a^m)^n=a^(mn)

=>x²×³

=>x⁶

(x²)³=x⁶

______________________________

iv)x-²=√x

I do not agree with Rakesh

He did wrong.

Justification:-

x-²

It is in the form of a^-n

a^-n=1/(a^n)

=>x-²

=>1/x²

x-²=1/x²

______________________________

v)3x-¹=1/3x

I do not agree with Rakesh

He did wrong

Justification:-

3x-¹

It is in the form of a^-n

a^-n=1/a^n

=>3x-¹

=>3(1/x)

=>3/x

3x-¹=3/x

_______________________________

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