5 tan^2A-5 tan A -1=0 then find the value of 5 tan A -cot A
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put tanA = x
5x² - 5x - 1 = 0
D = b²-4ac
= 25+20
=45
x = -b ±√D/2a
= 5 ±3√5 / 10
therefore
tanA = 5± 3√5 /10
cot A = 10 / 5+ 3√5
tanA + cotA = .........
5x² - 5x - 1 = 0
D = b²-4ac
= 25+20
=45
x = -b ±√D/2a
= 5 ±3√5 / 10
therefore
tanA = 5± 3√5 /10
cot A = 10 / 5+ 3√5
tanA + cotA = .........
Ananya002:
Thanks but do you have any other method to solve this question as per 10 th class formulaes
m in class 12
and so far i have not learnt any other way to solve this Q
I have learnt only this way
Ohhh! Its ok
And thanks
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