Question

5. যদি tan০ =
tana - tanß
হয়, তবে দেখাও যে,
1- tana tan B
sin28 =
sin 2a - sin 2ß
|
1- sin2a sin2B​

Answer 1

Answer:

Step-by-step explanation:

HEY MATE , HERE IS UR ANSWER.✌✌❤❤

Option ( A ) ZERO is the correct answer.

BRIEFLY SOLVED.....

A+B+C=180

B+C=180-A

sin(B+C)=sin(180-A)

sin(B+C)=sin A …(Because sin(180-y)=sin y)

Also cos B×cos C=cos A

tan A -tan B -tan C

=tan A -(sin B/cos B + sin C/cos C)

=tanA -(sinB×cosC + sinC×cos B)/(cosB×cosC)

=tanA -(sin(B+C))/(cosB×cosC)

=tan A -sin A/cos A

=tan A -tan A

=0

HOPE IT HELPS YOU.✌

#BE BRAINLY.❤❤

Answer 2

Answer: answer is zero (0)

Step-by-step explanation: