Math, asked by daddy768, 8 months ago

5 tan² A – 5 sec² A + 1 is equal to​

Answers

Answered by abhijeetvshkrma
238

= 5 tan² A–5 sec² A + 1

= -5 ( sec² A – tan² A )

= -5 ( 1 ) + 1

= -5+1

= -4

hence, answer is -4.

Answered by pulakmath007
5

5 tan² A – 5 sec² A + 1 = - 4

Given : 5 tan² A – 5 sec² A + 1

To find : The value

Formula : sec² A – tan² A = 1

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

5 tan² A – 5 sec² A + 1

Step 2 of 2 :

Simplify the given expression

5 tan² A – 5 sec² A + 1

= - 5 ( sec² A – tan² A ) + 1

= ( - 5 × 1 ) + 1

= - 5 + 1

= - 4

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