Question

5 tan² A – 5 sec² A + 1 is equal to.. *​

Answer 1

Answer:

-4

Step-by-step explanation:

5 tan² A – 5 sec² A + 1

5(tan² A – sec² A) + 1

5(-1) + 1 [sec² A - tan² A = 1]

-5 + 1

-4

Answer 2

Answer:

using identity = 1 + tan²= sec² => tan²-sec²= -1

5 tan² A – 5 sec² A + 1

5(tan²A - sec²A) +1

5×-1 +1

-5+1

-4

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