Question

5 tan² A – 5 sec² A + 1 is equal to 

a) 6

(6) -5

(c) 1

(d) -4

​

Answer 1

Answer:

-4

Step-by-step explanation:

5(tan² A – sec² A) + 1 =

-5 + 1 =

-4

pls mark as brainliest

Answer 2

(d) -4

Explanation:

=> 5 tan²A - 5 sec²A + 1

=> 5(tan²A - sec²A) + 1

=> 5(-1) + 1

[sec²A - tan²A = 1 or -(sec²A - tan²A) = tan²A - sec²A = -1]

=> -4

Please Thank Me

And Mark this as Brainliest