Question

5 tan² A-5 sec²A + 1 is equal to
(A) 1 (B) 0 (C) -4 (D) 2
​

Answer 1

Answer:-

(c) -4

Identity used:-

$\huge \fbox \blue{1+tan²A=sec²A}$

Solution:-

$\implies$ 5tan²A-5sec²A+1

$\implies$ 5tan²A-5(1+tan²A)+1

$\implies$ 5tan²A-5-5tan²A+1

$\implies$ -5+1

$\implies$ -4.

Answer 2

Answer:

$- 4 \: is \: the \: answer$

Step-by-step explanation:

5tan²A-5sec²A+1 = -5(sec²A-tan²A)+1

= -5(1)+1

= -4