Math, asked by amanraojii, 7 months ago

5 Tan2A - 5 Sec?A + 1 = ?

Answers

Answered by abhishek1007

1

Answer:

-4

Step-by-step explanation:

5(tan²A-sec²A) +1 ... (taking 5 common )

5[tan²A - ( 1+ tan²A) ] +1 ..... (1+tan²A = sec²A)

5(tan²A - 1 - tan²A ) +1

5(-1) +1

-5+1

-4

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