(5) tan⁴A + tan²A = sec⁴A- sec²A
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Answer:
LHS =sec^4A - sec^2A
=sec^2A (sec^2A-1)
=sec^2A .tan^2A {because sec^2A-tan^2A=1 }
=(1+tan^2A) tan^2A
=tan^4A+tan^2A =RHS
Hope it helps
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