Question

(5) $tate the smallest positive integer which
is divisible by 28 and 63 both​

Answer 1

Answer:

7 is smallest postive integer divisible by 28 and 63 both

Answer 2

Given:

Numbers: 28, 63

To find:

The smallest positive integer divisible by 28, 63

Solution:

The required number is 252.

We can obtain the value required by taking the LCM of the given terms.

The factors of numbers 28 and 63 are as follows-

28=2×2×7

63=3×3×7

So, the lowest and most common multiple of 28 and 63=2×2×3×3×7

=4×9×7

=252

So, the smallest integer divisible by 28 and 63 is 252.

Therefore, the required number is 252.