5). The age of a father is twice the sum of the ages of his 2 children .after 20 years his age will be equal to
the sum of the ages of his children ,find the ageof the Father.
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Answered by
1
Answer:
the father age be x.
two children age be y and z.
equation= x = 2(y+z)
After 20 years,
the father age x+20.
the two children age 2(y+z)+20
equation= x+20= 2(y+z)+20
...
now I hope u can solve this
AnushaKR:
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Answered by
3
Answer:let
Age of father be= X
Sum of children's ages = y
Atq,
X= 2y
X-2y=0....eq I
After 20 yrs
Father=X+20
Sum of ages of children=y+40
Atq,
X+20= y+40
X-y= 20...eq2
Solving by elimination
X-2y=0
X-y=20
- +. -
-1y=-20
Y=20
Sum of ages of children=20 yrs
Father's age=
2y= 2*20= 40
Therefore age of father is 40
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