Question

5.
The altitude of a parallelogram is thrice its corresponding base. If the area of the
parallelogram is 507 m^2?, find the base and the altitude.
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Answer 1

Answer:

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Answer 2

let base be x

and altitude be 3x

Area of parallelogram= base × altitude

507= x × 3x

507 = 3x^2

507/3 = x^2

169=x^2

√169= x

x=13

base=x=13

altitude=3x=3×13=39

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