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The angles of a triangle are (2x +30), (3x - 110)° and (x + 20
Find the val
In the given figure, side BC of AABC is extended to D.
please solve it
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the angles are (2x + 30), (3x - 110), (x + 20)
2x + 30 + 3x - 110 + x + 20 = 180 (angle sum property)
6x - 60 = 180
6x = 180 + 60 = 240
x = 240/6 = 40
2x + 30 = 80 + 30 = 110
3x - 110 = 120 -110 = 10
x + 20 = 40 +20 = 60
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