Question

5. The area of a rectangle and square are same. If
the side of a square is 80 m and length of
rectangular park is 200 m. Find breadth and
perimeter of the rectangle.​

Answer 1

Answer:

area of square = (side )^2

= 80^2

= 6400m^2

area of square = area of rectangle ( ATQ)

6400 = length × breadth

6400 = 200 × breadth

32m = breadth

Perimeter of rectangle = 2( length + breadth)

= 2(200+32)

= 2(232)

= 464 m

Answer 2

Given :

• Area of Rectangle and square are same .
• Side of square is 80 m and length of rectangle is 200 m.

To Find :

• Breadth and Perimeter of Rectangle .

Solution :

Firstly we will find the Area of Square :

Using Formula :

$\longmapsto\tt\boxed{Area\:of\:Square=Side\times{Side}}$

Putting Values :

$\longmapsto\tt{80\times{80}}$

$\longmapsto\tt\bf{6400\:{m}^{2}}$

Now ,

As Given that Area of Square is equal to the area of Rectangle . So ,

$\longmapsto\tt{Length=200\:m}$

Using Formula :

$\longmapsto\tt\boxed{Area\:of\:Rectangle=l\times{b}}$

Putting Values :

$\longmapsto\tt{6400=200\times{b}}$

$\longmapsto\tt{\cancel\dfrac{6400}{200}=b}$

$\longmapsto\tt\bf{32\:m=b}$

So , The Breadth of Rectangle is 32 m .

Now ,

$\longmapsto\tt{Length=200\:m}$

$\longmapsto\tt{Breadth=32\:m}$

Using Formula :

$\longmapsto\tt\boxed{Perimeter\:of\:Rectangle=2(l+b)}$

Putting Values :

$\longmapsto\tt{2(200+32)}$

$\longmapsto\tt{2(232)}$

$\longmapsto\tt\bf{464\:m}$

So , The Perimeter of Rectangle is 464 m .