Question

5. The area of a trapezium of height 3 m is 12 m². If one of the parallel sides is 2 m more than the other find
lengths of trapezium.
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Answer 1

$\sf\underline\green{Given:-}$

• Area of trapezium=12m²
• Height of trapezium=3m
• One of the parallel side is 2 more than other

$\sf\underline\green{To \:\: Find:-}$

• The other two sides=?

$\sf\underline\green{Formula \:\: Used:-}$

$\sf Area \:\: Of \:\: Trapezium = \frac{1}{2}(a+b)h$

$\sf\underline\green{Solution:-}$

Let the length of smaller square be x.

Second side=x+2

Substituting the values in formula

$\sf Area \:\: of \:\: Trapezium =\frac{1}{2}(a+b)h$

$\sf 12=\frac{1}{2}(x+x+2)3$

$\sf 12×2=(2x+2)×3$

$\sf \frac{24}{3}=(2x+2)$

$\sf 8-2=2x$

$\sf 6=2x$

$\sf x=\frac{6}{2}$

$\sf x=3$

$\sf x+2=5$

$\sf\blue{ The \: Length \: of \: sides \: are \: 3m \: and \: 5m }$