Question

5.
The atomic mass of N15 is 15.000108 a.m.u. and
that of 016 is 15.994915 a.m.u. If the mass of a
proton is 1.007825 a.m.u. then the minimum energy
provided to remove the least tightly bound proton is
(1) 0.013018 Mev
(2) 12.13 MeV
(3) 13.018 MeV
(4) 12.13 eV​

Answer 1

Answer:

12.13 eV is the ans... Dude!!