Math, asked by chetanreddy9032, 3 months ago


5. The average age of 4 sisters is 20. If the ages of
3 sisters are 16 yr, 18 yr and 20 yr, the age of
the fourth sister is.​

Answers

Answered by spacelover123
86

Given

  • The average age of 4 sisters is 20
  • Ages of 3 sisters are 16 years, 18 years and 20 years

__________________________________

To Find

  • The age of 4th sister.

__________________________________

Solution

Let's consider the age of the 4th sister as 'x'.

Formula to find Average ⇒ \dfrac{Sum \ of \ all \ observations }{No.\ of \ observations }

Average age ⇒ 20

Let's solve the following equation step-by-step to find the age of 4th sister.

\dfrac{16+18+20+x}{4} = 20

Step 1: Simplify the equation.

\dfrac{16+18+20+x}{4} = 20

\dfrac{54+x}{4} = 20

Step 2: Cross multiply.

54+x = 20\times 4

54 +x = 80

Step 3: Subtract 54 from both sides of the equation.

54 +x - 54= 80 - 54

x = 26

Let's verify if the age of the 4th sister is 26 years.

⇒  \dfrac{16+18+20+26}{4} = 20

\dfrac{80}{4} = 20

20 =20

∴ LHS = RHS

∴ The age of the 4th sister is 26 years.

__________________________________


mddilshad11ab: Perfect¶
Answered by Anonymous
107

Answer:

Given :-

  • The average age of 4 sister is 20. If the ages of 3 sisters and 16 yrs, 18 yrs and 20 yrs respectively.

To Find :-

  • What is the age of fourth sister.

Solution :-

Let, the fourth sister age be x years.

According to the question,

\sf \dfrac{16 + 18 + 20 + x}{4} =\: 20

By doing cross multiplication we get,

\sf 16 + 18 + 20 + x = 4(20)

\sf 34 + 20 + x =\: 4 \times 20

\sf 54 + x =\: 80

\sf x =\: 80 - 54

\sf\bold{\red{x =\: 26\: years}}

\therefore The age of fourth sister is 26 years .

\\

{\purple{\boxed{\large{\bold{VERIFICATION :-}}}}}

\sf \dfrac{16 + 18 + 20 + x}{4} =\: 20

By putting x = 26 we get,

\sf \dfrac{16 + 18 + 20 + 26}{4} =\: 20

By doing cross multiplication we get,

\sf 16 + 18 + 20 + 26 =\: 4(20)

\sf 34 + 46 =\: 4 \times 20

\sf\bold{\green{80 =\: 80}}

LHS = RHS

Hence, Verified


mddilshad11ab: perfect¶
Similar questions