Math, asked by sumana21pamidi, 3 months ago


5) The breadth of a rectangular park is twice its length. If the perimeter of the park is 216 meters.
find its dimensions​

Answers

Answered by sarthakgupta01
1

Answer:

Breadt of the field = 36m

Length of the field = 2×36 = 72m

Step-by-step explanation:

Let the breadth (b) of the rectangular field be x

∴length(l)=2x

As we know that, perimeter of rectangle (P) is given as-

P=2(l+b)

⇒P=2(2x+x)

⇒P=2(3x)

⇒P=6x

Given that perimeter (P) of the rectangular field is 216m

∴6x=216

⇒x =  216/6  = 36m

Therefore,

Breadt of the field = 36m

Length of the field = 2×36 = 72m

Hope it helps you, and please mark this answer as The Brainliest.

Answered by Anonymous
5

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Step-by-step-explanation:-

Given :-

  • Breadth of rectangle is twice its length
  • Perimeter of park is 216m

To find :-

Dimensions of rectangle

Consideration :-

As they given

breadth is twice its length

So,

  • Let length of rectangle is 'x' m
  • Breadth of rectangle is '2x' m

Formula implemented:-

Perimeter of rectangle = 2(l+b)

Solution:-

So,

length of rectangle is 'x' m

Breadth of rectangle is '2x' m

perimter is 216 m

So,

216 = 2 (l+b)

216 = 2 ( x + 2x)

216 = 2×3x

216 = 6x

216 /6 = x

x = 36 m = length

2x = 2×36 m

2x = 72m = breadth

So,

  • Length of rectangle is 36m
  • Breadth of recatngle is 72m

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