Question

5. The cost price of 16 articles is equal to selling price of 12 of them. Find the gain or
loss percent.​

Answer 1

Given :

CP of 16 articles = SP of 12 articles

To find :

Gain % or Loss %

Solution :

Let SP of 12 articles = CP of 16 articles = x

SP of one article = x / 12

CP of one article = x / 16

x / 12 > x / 16

⇒ SP > CP

So, the trasaction is Gain

Gain = SP - CP

= x / 12 - x / 16

= ( 4x - 3x ) / 48

= x / 48

Gain % = ( Gain / CP ) * 100

= [ ( x / 48 ) / ( x / 16 ) ] * 100

= ( x / 48 ) * ( 16 / x ) * 100

= 16 / 48 * 100

= 100 / 3

= 33 1/3 %

Therefore the Gain % is 33 1/3 %.

Answer 2

Answer:

$\large{\underline{\boxed{\mathfrak\blue{Gain\% \: earned = 33 \dfrac{1}{3} \% }}}}$

Question:-

The cost price of 16 articles is equal to selling price of 12 articles.Find the gain or loss percent.

Given:-

• CP of 16 articles = SP of 12 articles.

To find:-

• Gain% or loss% = ?

Solution:-

Let CP of 1 article be Rs.x & SP of 1 article = Rs.y

ATQ:-

⇒ 16x = 12y

⇒ x = 12y/16

⇒ x = 3y/4

⇒ x/y = 3/4

⇒ x : y = 3 : 4

•°•  CP of 1 article = Rs.3

•°•  SP of 1 article = Rs.4

$\because$ SP > CP

•°• It must be gain.

As, Gain = SP - CP

⇒ Gain = Rs.4 - Rs.3

⇒ Gain = Rs.1

$\rule{100}{2}$

Now,we know,

$\dag\: \: {\boxed{\sf\blue{Gain\% = \dfrac{Gain}{CP}\times 100 }}}$

➳ Gain% = (1 × 100)/3

➳ Gain% = 100/3

➳ Gain% = 33 ⅓ %

$\therefore{\underline{\sf{Gain\% \: earned = 33 \dfrac{1}{3} \% }}}$