Question

5. The distance between the points (0,0) and (-6, 8) is :​

Answer 1

Answer:

let A(0,0) &B(-6,8)

distance b/w AB=√(x2-x1)squre +(y2-y1)squre

√(-6-0)sq+(8-0)sq

√36+64

√100

10

Answer 2

Step-by-step explanation:

A B

Let AB the line .

Therefore,

distance of line AB =

$\sqrt{(x2 - x1) {}^{2} } + \sqrt{(y2 - y1) {}^{2} }$

$\sqrt{( - 6 - 0) {}^{2} } \sqrt{(8 - 0) {}^{2} }$

$\sqrt{( - 6) {}^{2} } + \sqrt{(8) {}^{2} }$

$\sqrt{36 + 64}$

=

$\sqrt{100}$

= 10 units