Question

5 The effective capacitance of the given
configuration is
CE)
1 uF 1 F
HH HE
1027
= 1 uF
2 uF​

Answer 1

Answer:

5/6 uF

Explanation:

1uF and 1uF are in series and 1uF and 2uF are in parallel

series = 1/1 +1/1 =2 uF

parallel = 1 + 2 = 3 uF

2 uF and 3 uF are connected in series

= 1/2 + 1/3 = 5/6 uF

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