Question

5. The energy required to melt lg. ice is 33J. The number of quanta of radiation of frequency 4.67 x 10power13 sec-1 that must be absorbed to melt 10g ice is
1) 1.065 x 10power22
2) 3.205 x 10power23
3) 9.076 x 10power2
4) None
PLEASE GIVE DETAILED ANSWER​

Answer 1

Answer:

Energy required to melt 1g ice =33J.

Energy required to melt 10g ice =33×10=330J.

Radiation frequency (ν)=4.67×10

13

s

−1

As we know, the energy of radiation is given by:

E=hν

Here, h= Planck's constant =6.62×10

−34

J.s

∴E=6.62×10

−34

×4.67×10

13

⇒E=3.09×10

−20

J

∴ No. of quanta required =

3.09×10

−20

330

=1.067×10

22

Hence, the correct option is (A).

Explanation:

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