Question

5 The following triplets form the length in cm of the sides of a triangle. State which of them form right-
angled triangles.
12.16.20
b 7,8,9
e 15, 28, 14
d 5.12, 13
e 16,63,65
f 9, 10, 12.

With Full explanation.
​

Answer 1

Answer:

12cm , 16cm ,20cm

Step-by-step explanation:

we know that ,

a right triangle has base a , perpendicular

height and a hypotenuse.

the hypotenuse is the longest side.

the height and base make 90°

angle.

there theorem as Pythagoras theorem .

it's state that ,

the sum of square and height and square base is equal to square of the hypotenuse.

so ,. the height of ab base as bc and hypotenuse as CA .

therefore , using Pythagoras theorem,

we can say that,

CA 2 = AB 2 + BC 2

so, hypotenuse is CA = 20 =bcm

i will consider ,

height AB = 16 = cm

and base BC = 12 = cm

using Pythagoras theorem ,

C A2 = AB 2 + BC 2

= 16 2 + 12 2

= 256 + 144

= 400

CA = 400 cm

therefore ,

CA = ✓ 400 = ✓20 × 20 = 20 cm

so, this is prove 12 cm ,16 cm, 20 cm