5. The force of repulsion between two point charges
is F, when these are 0.1 m apart. Now the point
charges are replaced by conducting spheres of radii
5 cm having the charge same as that of point
charges. The distance between their centres is
0.1 m, then the force of replusion will :-
(1) increase
(2) decrease
(3) remain same
(4) become10f÷9
Answers
Answered by
46
The repulsion force will decrease. Hence option no. 2 is the correct answer.
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Answered by
7
Answer:no change in force.
f=kq1q2/r^2
as r is distance between the centre of mass of bodies plus the separation and in case of spheres C.O.M Lies at the centre of sphere and given that the distance between the centres of spheres do not change and so the force.
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