Question

5.The graph of a linear equation x–5y+3=0 cuts the x-axis at the point

(-5,0)

(5,0)

(-3,0)

(3,0)​

Answer 1

Step-by-step explanation:

-3,0 is the answer....done

Answer 2

Given:

A linear equation x-5y+3=0 cuts the x-axis.

To find:

The point at which the linear equation cuts the x-axis.

• options are given: a) (-5,0), b) (5,0),c) (-3,0), d)(3,0)

Solution:

• We know that at x coordinate the value of y is zero for any point.
• So, y coordinate value of the point will be zero.
• As the point lies on the given linear equation, so putting y=0 at the given equation we get:
• $x-5*0+3=0\\x=-3$
• So the coordinate of the point is = (-3,0)

Final answer:

The graph of a linear equation x–5y+3=0 cuts the x-axis at the point (-3,0)[option c].