Question

5.The HCF of two numbers is 3 and their LCM is 54. If one of the numbers is 27, find the other
number.
if any one knows please answer fast​

Answer 1

answer:

lcm x hcf = Product of two numbers

lcm x hcf = a x b

 

so,

54 × 3 = 27 × b

~ 162 = 27b

~ b = 162/27

~ b = 6

Therefore,

Other number is 6

Verification :-

LCM × HCF = Product of two numbers

→ 54 × 3 = 27 × 6

→ 162 = 162

:)

Answer 2

Answer:

• 6

Step-by-step explanation:

Given

• H.C.F of two numbers = 3
• L.C.M of two numbers = 54
• One of the number (x) = 27

To find

• The other number (y)

Solution

⇒ H.C.F × L.C.M = Product of two numbers

• 3 × 54 = x × y
• 162 = 27 × y
• y = 162/27
• y = 6

∴ The other number (y) is 6.