Question

5. The largest possible number that
divides 280,1244 leaves remainder 4
and 2,
O (A). 136
O (B). 128
O (C). 138
O (D). 118​

Answer 1

Answer:

find the largest number which exactly divides 280 and 1245 leaving remainders 4 and 3 respectively, we subtract 4 and 3 from 280 and 1245.

280−4=276

1245−3=1242

276=2×2×3×23

1242=2×3×3×3×23

HCF=2×3×23=138