5. The length of a cuboid having breadth =4cm height= 4cm and
total surface area = 148 cm2, is
Answers
Answer :
›»› The length of the cuboid will be 7.25 cm.
Given :
- Breadth of a cuboid = 4 cm
- Height of a cuboid = 4 cm
- Total surface area of cuboid = 148 cm².
To Find :
- Length of a cuboid = ?
Solution :
Let us assume that the length of a cuboid is l cm.
As we know that
→ TSA of cuboid = 2(lb + bh + lh)
→ 148 = 2(l * 4 + 4 * 4 + l * 4)
→ 148 = 2(4l + 4 * 4 + l * 4)
→ 148 = 2(4l + 16 * l * 4)
→ 148 = 2(4l + 16 * 4l)
→ 148 = 2(8l + 16)
→ 148 = 2 * 8l + 2 * 16
→ 148 = 16l + 32
→ 148 - 32 = 16l
→ 116 = 16l
→ l = 116 ÷ 16
→ l = 7.25
║Hence, the length of the cuboid will be 7.25 cm.║
Extra Brainly Knowledge :
➝ Volume of cuboid = l * b * h.
➝ CSA of cuboid = 2(l + b)h.
➝ TSA of cuboid = 2(lb + bh + lh).
➝ CSA of cube = 4a².
➝ TSA of cube = 6a².
➝ Volume of cube = a³.
➝ Volume of cylinder = πr²h.
➝ TSA of cylinder = 2πrh + 2πr².
Where,
- l is the length.
- b is the breadth.
- h is the height.
- a is the side or edges.
- The value of π is 22/7 or 3.14.
- r is the Radius.
Answer :-
- Length of the cuboid is 7.25cm.
Given :-
- A cuboid having breadth as 4cm, height as 4cm and total surface area as 148cm².
To Find :-
- Length of the cuboid.
Solution :-
Here
- Breadth of the rectangle = 4cm
- Height of the rectangle = 4cm
- Length = ?
→ Total surface area is 148cm².
→ As we know that
total surface area of a rectangle is :-
2 (lb + bh + lh)
Where
- l = length
- b = breadth
- h = height
Put the values in the formula
2 [ l(4) + 4(4) + l(4) ] = 148
According to question :-
2 [ l(4) + 4(4) + l(4) ] = 148
⇒ 2 [ 4l + 16 + 4l ] = 148
⇒ 2 [ 8l + 16 ] = 148
⇒ 8l + 16 = 148/2
⇒ 8l + 16 = 74
⇒ 8l = 74 - 16
⇒ 8l = 58
⇒ l = 58/8
⇒ l = 7.25
Hence, the length of the cuboid is 7.25cm
Extra Shots :-
- Volume of a cuboid = l × b × h
- Total surface area of a cuboid = 2 (lb + bh + lh)
- Lateral surface area of a cuboid = 2h (l +b)
- Diagonal of a cuboid = √ (l² + b² + h²)