Question

5. The length of a rectangle is 10 m more than its breadth. If the perimeter of rectangle is 80 m, find the
dimensions of the rectangle.
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Answer 1

Answer:

let the breadth of a rectangle be x

so, length=x+10

perimeter of rectangle=2(l+b)

so, putting values,

2(x+x+10)

2(2x+10)

4x+20=80

4x=60

x=60/4

x=15

Answer 2

$\underline{ \purple{ \huge \mathtt{ \fbox{ \: Solution : \: \: }}}}$

Given ,

Perimeter of rectangle is 80 m

Let , the breadth of rectangle be x

So , length of rectangle = 10 + x

We know that , the perimeter of rectangle is given by

$\large \mathtt{ \fbox{Perimeter \: of \: rectangle = 2(Length + Breadth) }}$

Substitute the values , we obtain

$\sf \hookrightarrow 80 = 2(10 + x + x) \\ \\ \sf \hookrightarrow 80 = 20 + 4x \\ \\ \sf \hookrightarrow 60 = 4x\\ \\ \sf \hookrightarrow x = \frac{60}{4} \\ \\ \sf \hookrightarrow x = 15$

Hence , the length and breadth of rectangle are 25 m and 15 m