Question

5. The length of a rectangle is 8 cm and the width is 5 cm. If the length is greater by 2 cm, what should the width be so that the new rectangle has the same area as the first one?​

Answer 1

Answer:

Step-by-step explanation:

Let the length of the rectangle = l = 6 cm

The width of the rectangle = w = 4 cm

Area of the rectangle = A= l × w

= 6 × 4 = 24 sq cm

If the length is greater by 2

=> new length of rectangle = L = l + 2 = 6+2=8 cm

Area of new rectangle = A = 24

Width of new rectangle = W= ?

New rectangle area = L × W =>

A = L × W

24 = 8 × W = W = 3

Answer

New width of the rectangle is 3 cm to get the area of 24 sq cm

Answer 2

Answer:

The new width of the rectangle is $4cm$

Step-by-step explanation:

Given that the length of rectangle is $8 cm$

and the width of rectangle is $5 cm$

Now we know that

$Area\, of \,rectangle= length\times width$

Now we substitute the given values in the formula, we get

$Area\,of\,rectangle=8\times5\\ =40cm^2$

Now the length is greater by $2cm$

Therefore, the new length is $=8+2=10cm$

Now the width of the rectangle is

$Area\,of\,rectangle=length\times width\\40cm^2=10\times width\\\frac{40cm^2}{10}=width\\width=4cm$

Thus, the new width of the rectangle is $4cm$

Learn More:

Question:

If the length of rectangle is $12cm$ and breadth of rectangle is $4cm$ then find the area of rectangle?

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