Question

5:
The length of a rectangle shaped park exceeds its breadth by 17 meters. If the
perimeter of the park is 178 meters find the dimensions of the park?​

Answer 1

$\bold{Answer:}$

Let the breadth of the park be =x meters

Then the length of the park =x+17 meters

∴ perimeter of the park =2(length+breadth)

=2(x+17+x) meters

=2(2x+17) meters

But it is given that the perimeter of the rectangle is 178 meters

∴ 2(2x+17)=178

4x+34=178

4x=178−34

4x=144

x= $\bold{\frac{144}{4} }$=36

Therefore the breadth of the park =36 meters

Length of the park =36+17=53 meters.

Answer 2

Answer:

Let the breadth of the park be =x meters

Then the length of the park =x+17 meters

∴ perimeter of the park =2(length+breadth)

=2(x+17+x) meters

=2(2x+17) meters

But it is given that the perimeter of the rectangle is 178 meters

∴ 2(2x+17)=178

4x+34=178

4x=178−34

4x=144

x= \bold{\frac{144}{4} }

4

144

=36

Therefore the breadth of the park =36 meters

Length of the park =36+17=53 meters.