Question

5 The length of a rectangular park is three times its breadth. If the perimeter of the
park is 192 meters, find the dimensions of the park.
​

Answer 1

Answer:

if a rectangle parks a 192,hdk9697

Answer 2

We are given the Perimeter of a rectangular park = 192m.

∵ It is mentioned in the question that  the length of the rectangular park is three times its breadth

∴ Length = 3 × Breadth

So, Let us assume the breadth of the rectangular park as 'x'

∴ Length(l) = 3x $\longrightarrow$(1)

Formula of perimeter of a rectangle = 2(l+b)

2(l+b) = 192

l = 3x

b = x

2(3x+x) = 192

2 × 4x = 192

8x = 192

$\sf x = \dfrac{192}{8} = 24m$

Breadth of the  rectangular park = 24m.

Substituting value of 'x' in (1) , we get

Length = 3x = 3 × 24 = 72m.

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 72m}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 24m}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$