5
The length of an inclined plane at
30" is 20 m. A ring of mass 5 kg starts
rolling from rest from the top of the
plane, Calculate the velocity of the
ring at the bottom of the plane il
loss of kinetic energy is negligible (g
- 10 m/s2)
He
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Answer:
The change in kinetic energy when the ball reaches the bottom of the plane is 500J
loss due to friction =100J (20%of 500J )
net change in kinetic energy=400J
1/2×mass of ball×(velocity at base of the plane^2)-1/2×mass of the ball×(velocity at the top of the plane^2)=400J
1/2×mass of the ball ×velocity at the base of the plane=400J (because velocity at the top of the plane is 0)
1/2×5×(velocity at base ^2)=400J
velocity at base =4 (root10)
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