Question

5
The length of an inclined plane at
30" is 20 m. A ring of mass 5 kg starts
rolling from rest from the top of the
plane, Calculate the velocity of the
ring at the bottom of the plane il
loss of kinetic energy is negligible (g
- 10 m/s2)
He​

Answer 1

Answer:

The change in kinetic energy when the ball reaches the bottom of the plane is 500J

loss due to friction =100J (20%of 500J )

net change in kinetic energy=400J

1/2×mass of ball×(velocity at base of the plane^2)-1/2×mass of the ball×(velocity at the top of the plane^2)=400J

1/2×mass of the ball ×velocity at the base of the plane=400J (because velocity at the top of the plane is 0)

1/2×5×(velocity at base ^2)=400J

velocity at base =4 (root10)