Question

5. The lengths of a rectangle
is 5x²-6 and
its breadth is 2x²-2. Find its perimeter​

Answer 1

Step-by-step explanation:

L=5x²-6

W=2x²-2

P=2(L+W)

P=2(5x²-6+2x²-2)

P=2(7x²-8)

P=14x²-16

Answer 2

Given

we have given length and breadth of a Rectangle which is 5x²-6 & 2x²-2 respectively.

To Find

We have to find its perimeter.

$\sf\huge \mathbb{\underline{\underline{{Solution}}}}$

Since,we have given length and breadth so,we can easily calculate it's perimeter by using the formula :

Perimeter of Rectangle=2(l+b)

Where,l is the length ;b is the breadth

$\sf\implies \: Perimeter \: of \: Rectangle = 2(5 {x}^{2} - 6 + 2 {x}^{2} - 2)$

$\sf\implies2(7 {x}^{2} - 8)$

$\sf\implies14 {x}^{2} - 16$

$\sf \therefore \: Perimeter \: of \: Rectangle \: is \: 14 {x}^{2} - 16 \: sq.units$

Extra information=>

Perimeter is the total distance occupy by a solid 2D figure around its edge.

Rectangle

• A rectangle is a type of quadrilateral.
• Opposite sides are parallel & equal
• Sum of all Interior angles makes 360°
• Diagonals bisects each other and both diagonals are of same length.