5. The lengths of two simple pendula are in the ratio 2:3. Also, the ratio of the acceleration due
to gravity at the two places where they are set up is 3:2. Find the ratio of their frequencies.
Answers
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1
Answer:3:2
4:9
9:4
2:3
Answer :
D
Explanation:
Solution :
lA=l−x
lB=l+x
Where l=100cm
lA<lB
TA<TB
_TBTA=43
∴Sqrt(lBlA)=TBTA
l+xl−x=169.lx=257
x=725×100=28cm
Higher frequency ⇒ lower time period Regular
shorter pendulum = pendulum A
∴length of pendulum A=100 -28 =72 cm
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