5. The mass of an iron ball is 800 g. What should be the volume of the ball if the density is 7.87 g cm
Also find the density in the SI unit and the relative density.
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Answer:
volume of iron ball = 101.65 cm^3 and density of the iron ball in SI unit is 7.87*10^3 kg/m^3 and the Relative density is 7.87
Explanation:
mass of iron ball is 800g
density of iron ball is 7.87 g/cm^3
d=m/v
v=m/d
v=800/7.87= 101.65cm^3
therefore, volume is 101.65 cm^3
1g/cm^3= 10^3 kg/m^3
7.87 g/cm^3= 7.87* 10^3 kg/m^3
therefore, density in SI unit is 7.87*19^3 kg/m^3
Relative density= density of the substance/ density of water at 4°C
RD= 7.87/1
therefore, RD= 7.87
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