Question

5. The maximum acceleration the accelerator gives and the maximum retardation the brake can give to
a car are of equal magnitude and is 5 m/s2. The maximum distance the car can completes when starts from rest with in 1 minute just before it comes in rest
(A) 4500 m
(B) 2000 m
(C) 150 m
(D) 50 m​

Answer 1

Answer:

hey friend.

Explanation:

hi .how r u.

I think the answer is c

Answer 2

Answer:

OPTION (A) 4500 m

Explanation:Since the car starts from rest,

∴ initial velocity(u)=0

  time(t)= 1 minute = 60 seconds

Given;

same accleration and retardation of car = 5m/s²

total time = 60 seconds

∴ In first 30 seconds it acclerates and in next 30 seconds it retards i.e. de-acclerates and comes to rest.

Distance covered in first 30 seconds is same as distance covered in next 30 seconds.

Let distance in first 30 seconds = S

By using the formula:

S = ut+1/2at²

S = 0+1/2×5×30×30

S = 2250 m

∴ Total Distance = 2×S = 2×2250 = 4500 m (Ans)

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