Question

5.) The minute hand of a clock is 7cm long. Find the araa swept by
minute hand between 6:30p.m and 7.15 p. m​

Answer 1

Answer:

we know that one hour has 30 °

so 6:30-7:15 = 45 min

45/60×30= 45/2= 22.5 °

radius = 7 cm

θ = 22.5°

area of sector = θ/360×πr²

= 22.5/ 360× 22/7 × 7²

=9625 cm ²

Step-by-step explanation:

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Answer 2

Answer:

answer=25.6cm²(approx.)

length of the min hand of the clock(r)=7cm

to find:-area swept by the min hand

sol:-angle=360/60=6°

angle made in 10 min=10×6=60°

thus, area swept by the min hand=×r²×angle/360

>>>22/7×(7)²×60/360

>>>154/6

>>>25.6 cm²