Question

5. The moment of a forceacting along a line at a perpendicular distance of so cm from the axis of rotation, equals 25 N-m. Find the value of F​

Answer 1

Answer:

Moment of force = Force \times perpendicular distance of force from point of rotation

= F\times \bot distance

= 20N 0.5m

= 10Nm

Answer 2

Appropriate Question:

.The moment of a force acting along a line at a perpendicular distance of 50 cm from the axis of rotation, equals 25 N-m. Find the value of F.

Solution:

We have,

Perpendicular distance = 50cm = 0.5cm

Moment of force = 25N-m

Force = ??

We know that

Moment of force = Force × Perpendicular distance

∴ Force = Moment of force/Distance

= 25/0.5

= 25 × 10/5

= 50N