Question

5. The number of roots of equation x^6 - 7x^3 - 8 = 0 is:​

Answer 1

Step-by-step explanation:

there are six roots of equation

Let's find them

put x³=y. and x^6=y²

then our new equation is

y²-7y-8=0

y²-8y+y-8=0

y(y-8)+1(y-8)=0

(y+1)(y-8)=0

now

y+1=0 or y-8=0

we get

y=-1 and y=8

by resubmitting value we get

x³=y. so

x=1 ,2

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