Question

5. The number of zeros of x2 + 4x + 2
(a) 1
(b) 2
(C) 3
(d) none of these​

Answer 1

The number of zeroes are

x2 +4x+2

x2 +2x+2x+2

x(x+2) +x(x+2)

x+2=0 ,x+2=0

x=-2,x =-2

There fore the answer is option b 2

Answer 2

Answer:

(B)The number of zeros of given quadratic polynomial are 2

Step-by-step explanation:

The correct question is

The number of zeros of the polynomial  $x^{2} +4x+2$ are?

Let the given quadratic polynomial be

$f(x) = {x}^{2} + 4x + 2$

To find the zeros of any polynomial,we shall equate it to zero and then obtain the values which are called the zeroes of the polynomial.

For a quadratic polynomial,the method of obtaining zeroes is shown below

$a {x}^{2} + bx + c = 0 \\ = > x = \frac{ - b\pm \sqrt{ {b}^{2} - 4ac } }{2a}$

Hence zeros of quadratic polynomial are obtained in this way.We shall do the same method,for our given polynomial

$= > {x}^{2} + 4x + 2 = 0$

For the above polynomial,

a=1,b=4&c=2.Therefore,

$x = \frac{ - 4\pm\sqrt{ {4}^{2} - 4(1)(2)} }{2(1)} \\ = \frac{ - 4\pm\sqrt{8} }{2} = - 2\pm\sqrt{2}$

Hence the zeros of the quadratic polynomial are

$x_{1}=-2-\sqrt{2},x_{2}=-2 + \sqrt{2},$

Therefore,the number of zeros of given quadratic polynomial are 2

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