Math, asked by beverlyferrao2008, 7 months ago

5) The numbers 28743 and 64295 are divisible by 11 but not by 121. Which of the following numbers are NOT divisible by 11? A)28743+64295 B)28743 X 64295 C)2874364295 D)(28743 X 64295)÷121

Answers

Answered by MALEEHANOOD
20

To find the answer of this question we have to separate the odd and even numbers, like:

|10||9||8||7||6||5||4||3||2||1|

2 8 7 4 3 6 4 2 9 5

So as u can see, number above 5 is 1, so 1 is a odd number, so u have to conclude 5nas an odd number, u have to do the same to the other digits, then u have to do the following:

Odd- 5+2+6+4+8= 25

Even- 9+4+3+7+2= 25

After this, you have to subtract these two numbers:

25-25=0

Then you have to check if the number you get after subtracting is divisible by 11

In this case, you have to check if 0 is divisible by 11.

Pls mark as brainliest

Answered by vinod04jangid
0

Step-by-step explanation:

Given :

28743 and 64295 can both be divided by 11, but not by 121.

To prove:

(i) 28743+64295

(ii) 28743 X 64295

(iii) 2874364295

(iv)(28743 X 64295)÷121

Solution:

(i) 28743+64295

Take 28743 = 11x and 64295 = 11y, therefore.

28743+64295\\28743+64295 = 11x+11y

Thus,

11(x+y) multiple 11.

(ii) 28743 X 64295

28743 X 64295 = 11x*11y

= 11*(11xy), here is multiple of 11

This demonstrates that the multiple of 11 for 28743 by 64295.

(iii) 2874364295

A number can be divided by 11

if the difference between the sums of the odd and even numbers is zero or divisible by eleven.

here,

Digit sum with strange placements - Digit sum with even positions

= 2 +7 + 3 + 4 + 9 - (8 + 4 + 6 + 2 + 5) = 25 - 25 = 0

Therefore, 2874364295 can be divided by 11.

(iv)

(28743 X 64295)÷121

(28743 X 64295)÷121 =  (28743 X 64295)÷121

\frac{11x+11y}{121} =\frac{121xy}{121}

is not divisible by 11 (xy)

We can infer that xy is not divisible by 11 because neither integer can be divided by 121.

Thus, (28743 X 64295)÷121 is the number that cannot be divided by 11.

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