Math, asked by beverlyferrao2008, 10 months ago

5) The numbers 28743 and 64295 are divisible by 11 but not by 121. Which of the following numbers are NOT divisible by 11? A)28743+64295 B)28743 X 64295 C)2874364295 D)(28743 X 64295)÷121

Answers

Answered by MALEEHANOOD
20

To find the answer of this question we have to separate the odd and even numbers, like:

|10||9||8||7||6||5||4||3||2||1|

2 8 7 4 3 6 4 2 9 5

So as u can see, number above 5 is 1, so 1 is a odd number, so u have to conclude 5nas an odd number, u have to do the same to the other digits, then u have to do the following:

Odd- 5+2+6+4+8= 25

Even- 9+4+3+7+2= 25

After this, you have to subtract these two numbers:

25-25=0

Then you have to check if the number you get after subtracting is divisible by 11

In this case, you have to check if 0 is divisible by 11.

Pls mark as brainliest

Answered by vinod04jangid
0

Step-by-step explanation:

Given :

28743 and 64295 can both be divided by 11, but not by 121.

To prove:

(i) 28743+64295

(ii) 28743 X 64295

(iii) 2874364295

(iv)(28743 X 64295)÷121

Solution:

(i) 28743+64295

Take 28743 = 11x and 64295 = 11y, therefore.

28743+64295\\28743+64295 = 11x+11y

Thus,

11(x+y) multiple 11.

(ii) 28743 X 64295

28743 X 64295 = 11x*11y

= 11*(11xy), here is multiple of 11

This demonstrates that the multiple of 11 for 28743 by 64295.

(iii) 2874364295

A number can be divided by 11

if the difference between the sums of the odd and even numbers is zero or divisible by eleven.

here,

Digit sum with strange placements - Digit sum with even positions

= 2 +7 + 3 + 4 + 9 - (8 + 4 + 6 + 2 + 5) = 25 - 25 = 0

Therefore, 2874364295 can be divided by 11.

(iv)

(28743 X 64295)÷121

(28743 X 64295)÷121 =  (28743 X 64295)÷121

\frac{11x+11y}{121} =\frac{121xy}{121}

is not divisible by 11 (xy)

We can infer that xy is not divisible by 11 because neither integer can be divided by 121.

Thus, (28743 X 64295)÷121 is the number that cannot be divided by 11.

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