Question

5. The odometer of a car reads 57321.0 km when the clock shows the time 08:30 AM What is the distance moved by the car if at 08:50 AM the odometer reading has changed to 57336.0 km? Calculate the speed of the car in km/min during this time Express the speed in km/h also​

Answer 1

Answer:

Solution:

Solution:The initial reading of the odometer of the car =57321.0 km

Solution:The initial reading of the odometer of the car =57321.0 kmThe final reading of the odometer of the car = 57336.0 km

Solution:The initial reading of the odometer of the car =57321.0 kmThe final reading of the odometer of the car = 57336.0 kmThe car starts at 8:30 AM and stops at 8:50 AM.

Solution:The initial reading of the odometer of the car =57321.0 kmThe final reading of the odometer of the car = 57336.0 kmThe car starts at 8:30 AM and stops at 8:50 AM.Distance covered by car = (57336 - 57321) km = 15 km

Solution:The initial reading of the odometer of the car =57321.0 kmThe final reading of the odometer of the car = 57336.0 kmThe car starts at 8:30 AM and stops at 8:50 AM.Distance covered by car = (57336 - 57321) km = 15 kmTime taken between 08:30 AM to 08:50 AM = 20 minutes = 20/60 hour = 1/3 hour

Solution:The initial reading of the odometer of the car =57321.0 kmThe final reading of the odometer of the car = 57336.0 kmThe car starts at 8:30 AM and stops at 8:50 AM.Distance covered by car = (57336 - 57321) km = 15 kmTime taken between 08:30 AM to 08:50 AM = 20 minutes = 20/60 hour = 1/3 hourSo Speed in km/min

Solution:The initial reading of the odometer of the car =57321.0 kmThe final reading of the odometer of the car = 57336.0 kmThe car starts at 8:30 AM and stops at 8:50 AM.Distance covered by car = (57336 - 57321) km = 15 kmTime taken between 08:30 AM to 08:50 AM = 20 minutes = 20/60 hour = 1/3 hourSo Speed in km/minSpeed = (Distance travelled)/ (Time)

Solution:The initial reading of the odometer of the car =57321.0 kmThe final reading of the odometer of the car = 57336.0 kmThe car starts at 8:30 AM and stops at 8:50 AM.Distance covered by car = (57336 - 57321) km = 15 kmTime taken between 08:30 AM to 08:50 AM = 20 minutes = 20/60 hour = 1/3 hourSo Speed in km/minSpeed = (Distance travelled)/ (Time)= (15km)/ (20min)

Solution:The initial reading of the odometer of the car =57321.0 kmThe final reading of the odometer of the car = 57336.0 kmThe car starts at 8:30 AM and stops at 8:50 AM.Distance covered by car = (57336 - 57321) km = 15 kmTime taken between 08:30 AM to 08:50 AM = 20 minutes = 20/60 hour = 1/3 hourSo Speed in km/minSpeed = (Distance travelled)/ (Time)= (15km)/ (20min)= 0.75km/min

Solution:The initial reading of the odometer of the car =57321.0 kmThe final reading of the odometer of the car = 57336.0 kmThe car starts at 8:30 AM and stops at 8:50 AM.Distance covered by car = (57336 - 57321) km = 15 kmTime taken between 08:30 AM to 08:50 AM = 20 minutes = 20/60 hour = 1/3 hourSo Speed in km/minSpeed = (Distance travelled)/ (Time)= (15km)/ (20min)= 0.75km/minSpeed in km/h Speed = (Distance travelled)/ (Time)

Solution:The initial reading of the odometer of the car =57321.0 kmThe final reading of the odometer of the car = 57336.0 kmThe car starts at 8:30 AM and stops at 8:50 AM.Distance covered by car = (57336 - 57321) km = 15 kmTime taken between 08:30 AM to 08:50 AM = 20 minutes = 20/60 hour = 1/3 hourSo Speed in km/minSpeed = (Distance travelled)/ (Time)= (15km)/ (20min)= 0.75km/minSpeed in km/h Speed = (Distance travelled)/ (Time)= (15km)/ (1/3h)

Solution:The initial reading of the odometer of the car =57321.0 kmThe final reading of the odometer of the car = 57336.0 kmThe car starts at 8:30 AM and stops at 8:50 AM.Distance covered by car = (57336 - 57321) km = 15 kmTime taken between 08:30 AM to 08:50 AM = 20 minutes = 20/60 hour = 1/3 hourSo Speed in km/minSpeed = (Distance travelled)/ (Time)= (15km)/ (20min)= 0.75km/minSpeed in km/h Speed = (Distance travelled)/ (Time)= (15km)/ (1/3h)= (15 x 3) km/ (1h)

Solution:The initial reading of the odometer of the car =57321.0 kmThe final reading of the odometer of the car = 57336.0 kmThe car starts at 8:30 AM and stops at 8:50 AM.Distance covered by car = (57336 - 57321) km = 15 kmTime taken between 08:30 AM to 08:50 AM = 20 minutes = 20/60 hour = 1/3 hourSo Speed in km/minSpeed = (Distance travelled)/ (Time)= (15km)/ (20min)= 0.75km/minSpeed in km/h Speed = (Distance travelled)/ (Time)= (15km)/ (1/3h)= (15 x 3) km/ (1h)= 45km/h

Step-by-step explanation:

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Answer 2

Solution:

The initial reading of the odometer of the car =57321.0 km

The final reading of the odometer of the car = 57336.0 km

The car starts at 8:30 AM and stops at 8:50 AM.

Distance covered by car = (57336 - 57321) km = 15 km

Time taken between 08:30 AM to 08:50 AM = 20 minutes = 20/60 hour = 1/3 hour

So Speed in km/min

Speed = (Distance travelled)/ (Time)

= (15km)/ (20min)

= 0.75km/min

Speed in km/h Speed = (Distance travelled)/ (Time)

= (15km)/ (1/3h)

= (15 x 3) km/ (1h)

= 45km/h

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