5. The parallel sides of a trapezium are 15 m
and 8 m and the distance between them is
12 m. What is the area of the trapezium ?
Answers
Answered by
5
Area of a trapezium
= 1/2(a+b)h
= 1/2(15+8)12
= 1/2 × 23 × 12
= 6 × 23
= 138 m^2
Answered by
1
Solution :
Let us consider a trapezium ABCD .
Its parallel sides are AB and DC .
From the information given in the question, we can say that , AB = 15 cm and DC = 8 cm.
Now, the perpendicular distance between these sides is 12 m.
Area of A Trapezium :
> 1/2 * (Sum of parallel sides ) * ( Corresponding perpendicular distance between them )
> 1/2 * ( 15 + 8 ) * ( 12 )
> ( 15 + 8) * 6
> 23 * 6
> 138 m^2 .
This is the required area of the given trapezium .
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